Respuesta :
Answer:
initial velocity is 3.62 m/s
Explanation:
given data
high = 1.32 m
length = 1.88 m
to find out
initial velocity
solution
we consider here top height point a and b point at ground and c point at distance 1.88 m away from b on ground
and x is horizontal component and y is vertical component
so at point A initial velocity is Va = Vx i
and at point c velocity = Vc = Vx i + Vy j
first we calculate time taken when it come down by distance formula
distance = 1/2 ×gt² ..............1
1.32 = 1/2 ×(9.8)t²
t = 0.519 sec
so velocity x = distance / time
velocity x = [tex]\frac{1.88}{0.519}[/tex]
velocity x = 3.622 m/s
so initial velocity is 3.62 m/s
Answer:
3.62 m/s
Explanation:
h = 1.32 m
d = 1.88 m
Let u be the initial horizontal velocity and the time taken by the board to reach the ground is t.
Use second equation of motion in vertical direction
[tex]s=ut+0.5at^{2}[/tex]
1.32 = 0 + 0.5 x 9.8 x t^2
t = 0.52 second
The horizontal distance = horizontal velocity x time
1.88 = u x 0.52
u = 3.62 m/s
Thus, the nitial speed of the skate board is 3.62 m/s.
