Answer:
(a) 0.459 Jg⁻¹°C⁻¹
(b) 22 Jmol⁻¹°C⁻¹
(c) 0.72 moles
Explanation:
(a) The specific heat capacity can be calculated using the following equation:
Q = mcΔt, where Q is the heat energy, m is the mass, c is the specific heat capacity, and Δt is the temperature change from initial to final.
Rearranging the equation to solve for c gives:
c = Q / (mΔt) = (312J) / ((34.0g)(44.0°C - 24°C) = 0.459 Jg⁻¹°C⁻¹
(b) To find the molar specific heat, grams in the above result must be converted to moles using the mass per mole:
(0.459 Jg⁻¹°C⁻¹)(47g/mol) = 22 Jmol⁻¹°C⁻¹
(c) The numer of moles present are found by converting grams to moles using the mas per mole:
(34.0g)(mol/47g) = 0.72 moles
