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Two very small 8.55-g spheres, 15.0 cm apart from center to center, are charged by adding equal numbers of electrons to each of them.

(a)Disregarding all other forces, how many electrons would you have to add to each sphere so that the two spheres will accelerate at 25.0g when released?
(b)Which way will they accelerate?

Respuesta :

Answer:

1.43 x 10¹⁷.

They will accelerate away from each other.

Explanation:

Force on each charged sphere F = mass x acceleration

= 8.55 x 10⁻³ x 25 x 9.8

= 2.095 N

Let Q be the charge on each sphere

F = [tex]\frac{9\times10^9\times Q^2}{(15\times10^{-2})^2}[/tex]

2.095 =[tex]\frac{9\times10^9\times Q^2}{(15\times10^{-2})^2}[/tex]

Q² =[tex]\frac{2.095\times(15)^2\times10^{-4}}{9\times10^9}[/tex]

Q = 2.289 X 10⁻⁶

No of electrons = Charge / charge on a single electron

= [tex]\frac{2.289\times10^{-6}}{1.6\times10^{-19}}[/tex]

=1.43 x 10¹³.

They will accelerate away from each other.

The number of electrons would have to add to each sphere to accelerate at 25.0g is 1.43×10¹³ and accelerate away from each other.

What is electric force?

Electric force is the force of attraction of repulsion between two bodies.

According to the Coulombs law, the force of attraction of repulsion between charged two bodies is directly proportional to the product of charges of them and inversely proportional to the square of distance between them. It can be given as,

[tex]F=\dfrac{KQ_1Q_2}{r^2}[/tex]

Here, (k) is the coulombs constant,  (q1 and q2) is the charges of two bodies and (r) is the distance between the two charges.

Two very small 8.55-g spheres, 15.0 cm apart from center to center, are charged by adding equal numbers of electrons to each of them.

  • (a) The Number of electrons would have to add to each sphere-

Two spheres accelerate at 25.0g when released, and the mass of each sphere is 8.55 g. Thus, the force on the sphere can be given as,

[tex]F=8.55\times{10^{-3}}\times25\times9.8\\F=2.095\rm \;N[/tex]

Two very small spheres are 15.0 cm apart from center to center, are charged by adding equal numbers of electrons to each of them.As the charge on both the sphere is same (say Q) Put these values in the above formula as,

[tex]2.095=\dfrac{(9\times10^{9})QQ}{(15\times10^{-2})^2}\\Q=2.289\times10^{-6}\rm \;C[/tex]

It is known that the charge on one electron is 1.6×10⁻¹⁹ C. Thus the number of electron in the above charge is,

[tex]n=\dfrac{2.289\times10^{-6}}{1.6\times10^{-19}}\\n=1.43\times10^{13}[/tex]

  • (b)Direction of acceleration-

The direction of acceleration of both the sphere will be opposite to each other. Thus, they accelerate away from each other.

Hence, the number of electrons would have to add to each sphere to accelerate at 25.0g is 1.43×10¹³ and accelerate away from each other.

Learn more about the electric force here;

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