Answer:
[tex]q_1 = 2\mu C[/tex]
[tex]q_2 = 9 \mu C[/tex]
Explanation:
As we know that
[tex]q_1 + q_2 = 11 C[/tex]
also we know that
[tex]F = \frac{kq_1q_2}{r^2}[/tex]
[tex]8 \times 10^{-3} = \frac{(9 \times 10^9)(q_1q_2)}{4.5^2}[/tex]
here we have
[tex]1.8 \times 10^{-11} = q_1 q_2[/tex]
so now we have
[tex]1.8 \times 10^{-11} = (11 - q_1) q_1[/tex]
so we will have
[tex]q_1 = 2\mu C[/tex]
[tex]q_2 = 9 \mu C[/tex]