Respuesta :
Answer: The mass of air present in the room is 37.068 kg
Explanation : Given,
Length of the room = 10.0 ft
Breadth of the room = 11.0 ft
Height of the room = 10.0 ft
To calculate the volume of the room by using the formula of volume of cuboid, we use the equation:
[tex]V=lbh[/tex]
where,
V = volume of the room
l = length of the room
b = breadth of the room
h = height of of the room
Putting values in above equation, we get:
[tex]V=10.0ft\times 11.0ft\times 10.0ft=1100ft^3=31148.53L[/tex]
Conversion used : [tex]1ft^3=28.3168L[/tex]
Now we have to calculate the mass of air in the room.
[tex]Density=\frac{Mass}{Volume}[/tex]
[tex]1.19g/L=\frac{Mass}{31148.53L}[/tex]
[tex]Mass=37066.7507g=37.068kg[/tex]
Conversion used : (1 kg = 1000 g)
Therefore, the mass of air present in the room is 37.068 kg
Answer: There are 37 kg of air in the room.
Explanation:
To calculate the volume of cuboid (room), we use the equation:
[tex]V=lbh[/tex]
where,
V = volume of cuboid
l = length of room = 11 ft
b = breadth of room = 10 ft
h = height of room= 10 ft
Putting values in above equation, we get:
[tex]V=10\times 11\times 10=1100ft^3=1100\times 28.3L=31130L[/tex] (Conversion factor: [tex]1ft^3=28.3L[/tex]
To calculate mass of a substance, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
We are given:
Density of air = 1.19 g/L
Volume of air = volume of room = 31130 L
Putting values in above equation, we get:
[tex]1.19g/L=\frac{\text{Mass of air}}{31130L}\\\\\text{Mass of air}=37000g=37.0kg[/tex] (1kg=1000g)
Hence, the mass of air is 37 kg.
