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A small metal sphere of mass 3.1 g and charge 2.6 μC is fired with an initial speed of 5.6 m/s directly toward the center of a second metal sphere carrying charge 3.4 μC. This second sphere is held fixed. If the spheres are initially a large distance apart, how close do they get to each other? Treat the spheres as point charges.

Respuesta :

Answer:

d = 1.636 m

Explanation:

Initially charged sphere are far apart so their potential energy is zero . Kinetic energy will be of small sphere

K E of small sphere

= 1/2 m v²

= .5 x 3.1 x 10⁻³ x ( 5.6)²

=48.608 x 10⁻³ J

If d be the distance of closest approach between them , potential energy of

Charges

= k q₁ x q₂ / d²

[tex]\frac{9\times10^9\times2.6\times10^{-6}\times3.4\times10^{-6}}{d^2}[/tex]

= [tex]\frac{79.56\times10^{-3}}{d^2}[/tex]

Total kinetic energy at this point will be zero.

Applying the theory of conservation of mechanical energy

Potential energy at distance d = Kinetic energy at infinity

48.608 x 10⁻³ = [tex]\frac{79.56\times10^{-3}}{d^2}[/tex]

d = 1.636 m