Answer:
Explanation:
From literature, we know that the typical pka of a lysine side is 10.3.
Then we use the Henderson-Hasselbalch equation:
[tex]pH=pka+log\frac{[A^{-} ]}{[HA]}[/tex]
In this case, [A⁻] is the concentration of deprotonated lysine, and [HA] is the concentration of protonated lysine.
We put the data from the problem in the equation and calculate the ratio of deprotonated to protonated lysine:
[tex]7.5=10.5+log\frac{[A^{-} ]}{[HA]}\\-3.0=log\frac{[A^{-} ]}{[HA]}\\10^{-3.0}=\frac{[A^{-} ]}{[HA]}\\0.001=\frac{[A^{-} ]}{[HA]}[/tex]