Answer:
The wavelength of this wave is 1.01 meters.
Explanation:
The variation in the pressure of helium gas, measured from its equilibrium value, is given by :
[tex]\Delta P=2.9\times 10^{-5}\ cos(6.2x-3000t)[/tex]..............(1)
The general equation is given by :
[tex]\Delat P=P_o\ cos(kx-\omega t)[/tex]...........(2)
On comparing equation (1) and (2) :
[tex]k=6.2[/tex]
Since, [tex]k=\dfrac{2\pi}{\lambda}[/tex]
[tex]\dfrac{2\pi}{\lambda}=6.2[/tex]
[tex]\lambda=1.01\ m[/tex]
So, the wavelength of this wave is 1.01 meters. Hence, this is the required solution.
