The vector y = ai + bj is perpendicular to the line ax + by = c. Use this fact to find an equation of the line through P perpendicular to v. Then draw a sketch of the line including v as a vector starting at the origin. P(-1,-9)v = -4i + j The equation of the line is _____.

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Answer:

[tex]-4x+y=-5[/tex]

Step-by-step explanation:

It is given that he vector y = ai + bj is perpendicular to the line ax + by = c.

Given given point is P(-1,-9) and given vector is v = -4i + j.

Here, a = -4 and b= 1.

We need to find the equation of the line through P perpendicular to v.

Using the above fact, the vector v = -4i + j is perpendicular to the line

[tex](-4)x+(1)y=c[/tex]

[tex]-4x+y=c[/tex]          ... (1)

The line passes through the point (-1,-9).

Substitute x=-1 and y=-9 in the above equation to find the value of c.

[tex]-4(-1)+(-9)=c[/tex]

[tex]4-9=c[/tex]

[tex]-5=c[/tex]

The value of c is -5.

Substitute c=-5 in equation (1).

[tex]-4x+y=-5[/tex]

Therefore the equation of line which passes through P and perpendicular to v is -4x+y=-5.

The line equation is [tex]-4x + y = -5[/tex]

Calculation of Line equation:

Using formula/ standard equation of a line:

[tex]\to ax+by=C[/tex]

[tex]\to a=-4\\\\\to b=1 \\\\\to (-4).x +1.y = C\\\\ \to - 4.x + y = c\\\\[/tex]

When the line passes through [tex](-1,-9)[/tex]:

[tex]\to -4(-1)+(-9) = C\\\\ \to 4+(-9) = C\\\\ \to -5=c\\\\[/tex]

Therefore, the line equation is [tex]-4x + y = -5[/tex].

Find out more information about the line equation here:

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