Answer:
1.336 m
Explanation:
q = - 3.77 micro C at y = 0 m
Q = - 4.92 micro C at y = 2.86176 m
Let the electric field is zero at P which is at a distance y from origin.
Electric field at P due to q is equal to the electric field at P due to Q.
[tex]E_{q}=E_{Q}[/tex]
[tex]\frac{kq}{OP^{2}}=\frac{kQ}{AP^{2}}[/tex]
[tex]\frac{3.77}{y^{2}}=\frac{4.92}{\left ( 2.86176-y \right )^{2}}[/tex]
[tex]\frac{\left ( 2.86176-y \right )}{y}}=1.142[/tex]
2.86176 - y = 1.142 y
2.142 y = 2.86176
y = 1.336 m
Thus, the electric field is zero at y = 1.336 m.
