Answer:
507599.78 J
Explanation:
Charge input = current x time
=15 x 53 x 60
= 47000 coulomb
increase in voltage
= 12.6 - 9 = 3.6
capacity of the battery C = Charge input / increase in voltage
= 47000 / 3.6 = 13055.55
energy of the capacitor = 1/2 CV²
Initial energy of car battery = .5 x 13055.55 x 9 x 9
= 528749.77 J
Final energy of car battery
= .5 x 13055.55 x 12.6 x 12.6
= 1036349.55
Increase in energy = 507599.78 J