Answer:
d) Is the thermal conductivity of the medium constant or variable.
Explanation:
As we know that
Heat equation with heat generation at unsteady state and with constant thermal conductivity given as
[tex]\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}+\dfrac{\dot{q}_g}{K}=\dfrac{1}{\alpha }\dfrac{dT}{dt}[/tex]
With out heat generation
[tex]\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}[/tex]
In 2 -D with out heat generation with constant thermal conductivity
[tex]\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}[/tex]
Given equation
[tex]\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{a }\dfrac{dT}{dt}[/tex]
So we can say that this is the case of with out heat generation ,unsteady state and with constant thermal conductivity.
So the option d is correct.
d) Is the thermal conductivity of the medium constant or variable.
