Answer:
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Step-by-step explanation:
The height h of the ball is modeled by the following equation
[tex]h(t)=-16t^2+32t+48[/tex]
The problem want you to find the times the ball will be 48 feet above the ground.
It is going to be when:
[tex]h(t) = 48[/tex]
[tex]h(t)=-16t^{2}+32t+48[/tex]
[tex]48=-16t^{2}+32t+48[/tex]
[tex]0=-16t^{2}+32t+48 - 48[/tex]
[tex]16t^{2} - 32t = 0[/tex]
We can simplify by 16t. So
[tex]16t(t-2)= 0[/tex]
It means that
16t = 0
t = 0
or
t - 2 = 0
t = 2
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
