Answer:
length = 2L, mass = M/2, and maximum angular displacement = 1 degree
Explanation:
We consider only small amplitude oscillations (like in this case), so that the angle θ is always small enough. Under these conditions recall that the equation of motion of the pendulum is:
[tex]\ddot{\theta}=\frac{g}{l}\theta[/tex]
And its solution is:
[tex]\theta=Asin(\omega t + \phi)[/tex]
Where [tex]\omega=\sqrt\frac{g}{l}[/tex] are the angular frequency of the oscillations, from which we determine their period:
[tex]T=\frac{2\pi}{\omega}\\T=2\pi\sqrt\frac{l}{g}[/tex]
Therefore the period of a pendulum will only depend on its length, not on its mass or angle, for angles small enough. So, the answer is the one with the greater length.
