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13-09-2019
Physics

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The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of the axon (nerve fiber). If the nerve cell connecting the spinal cord to your feet is 1.2 m long, and the nerve impulse speed is 15 m/s, how long (in s) does it take for the nerve signal to travel this distance?

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shirleywashington shirleywashington

16-09-2019

Answer:

0.08

Explanation:

Length the impulse has to travel i.e., the length of the nerve cell connecting the spinal cord to your feet = 1.2 m

Speed at which the impulse travels in the nerve cell = 15 m/s

Time = Distance / Speed

[tex]\text{Time}=\frac{1.2}{15}\\\Rightarrow \text{Time}=0.08\ s[/tex]

∴ Time taken by the impulse to travel the distance from the nerve cell connecting the spinal cord to your feet is 0.08 seconds

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