Answer:
[tex]W=5743.1077\ J[/tex]
Explanation:
The expression for the work done is:
[tex]W=RT \ln \left( \dfrac{P_1}{P_2} \right)[/tex]
Where,
W is the amount of work done by the gas
R is Gas constant having value = 8.314 J / K mol
T is the temperature
P₁ is the initial pressure
P₂ is the final pressure
Given that:
T = 300 K
P₁ = 10 bar
P₂ = 1 bar
Applying in the equation as:
[tex]W=8.314\times 300 \ln \left( \dfrac{10}{1} \right)[/tex]
[tex]W=300\times \:8.314\ln \left(10\right)[/tex]
[tex]W=2.30258\times \:2494.2[/tex]
[tex]W=5743.1077\ J[/tex]
