46.3 wt%A, 23.15 wt%B and 30.55 wt%C. Assume the densities in g/cu.cm of A, B andC are 2.68, 5.86 and 10.39, respectively. Determine the approximate density in g/cu.cm if the alloy is composed of

Respuesta :

Answer : The approximate density is [tex]5.77g/cm^3[/tex]

Explanation :

The formula used to calculate the density of the mixture is,

[tex]\rho=[(m_A\times \rho_A)+(m_B\times \rho_B)+(m_C\times \rho_C)][/tex]

where,

[tex]\rho[/tex] = density of mixture = ?

[tex]m_A[/tex] = mass of fraction of component A = 46.3 % = 0.463

[tex]m_B[/tex] = mass of fraction of component B = 23.15 % = 0.2315

[tex]m_C[/tex] = mass of fraction of component C = 30.55 % = 0.3055

[tex]\rho_A[/tex] = density of component A = [tex]2.68g/cm^3[/tex]

[tex]\rho_B[/tex] = density of component B = [tex]5.86g/cm^3[/tex]

[tex]\rho_C[/tex] = density of component C = [tex]10.39g/cm^3[/tex]

Now put all the given values in the above formula, we get:

[tex]\rho=[(0.463\times 2.68)+(0.2315\times 5.86)+(0.3055\times 10.39)][/tex]

[tex]\rho=5.77g/cm^3[/tex]

Therefore, the approximate density is [tex]5.77g/cm^3[/tex]