Answer:
The shear modulus of the polymer is 5 MPa
Solution:
As per the question:
displacement of the top plate, d = 2 mm = 0.002 m
Horizontal Force, P = 2 kN = 2000 N
Width of the block, w = 100 mm = 0.1 m
By small angle analysis:
Angle, [tex]\gamma = \frac{2}{200} = 0.01 rad[/tex]
Now,
Stress, [tex]\tau [/tex] = [tex]\frac{P}{Area} = \frac{2000}{0.4\times 0.1} = 50000 Pa[/tex]
[tex]G = \frac{\tau}{\gamma} = \frac{50000}{0.01} = 5 MPa[/tex]
