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Suppose a basketball team had a season of games with the following characteristics: Of all the games, 60% were at-home games. Denote this by H (the remaining were away games). Of all the games, 25% were wins. Denote this by W (the remaining were losses). Of all the games, 20% were at-home wins. Of the at-home games, what proportion of games were wins? (Note: Some answers are rounded to two decimal places.)

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Answer:

1/3 of the at home games were wins

Step-by-step explanation:

We need to set the proportion for wined games at home. In the upper part we should put the games that were wined at home and in the under part the games played at home. Then

[tex]\frac{WH}{H} =\frac{20}{60}=\frac{2}{6} = \frac{1}{3}[/tex]

When we reduce the fraction we get that 1/3 of the games at home were wined

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