Answer:
Option A
Solution:
As per the question:
The distance covered by the woman in the North direction, d = 3000 m
Time taken to travel in North direction, t = 25.0 min = 1500 s
Velocity of woman in the south direction, v = 2.00 m/s
Time taken in the south direction, t' = 60.0 min = 3600 s
Now,
The distance covered in the south direction, d' = vt' = [tex]2.00\times 3600 = 7200\ m[/tex]
Now, the total displacement is given by:
D = d' - d = 7200 - 3000 = 4200 m in South
(a) Average velocity of the woman in the whole journey is given by:
[tex]v_{avg} = \frac{Total\ displacement}{Total\ time} = \frac{4200}{t + t'}[/tex]
[tex]v_{avg} = \frac{4200}{1500 + 3600} = 0.8235\ m/s[/tex] ≈ 0.824 m/s South
