Answer:
(a) The volume of water in the quarry is 6.496 x 10⁷ m³.
(b) The total mass of mercury is 1.19 x 10⁻³ kg.
Explanation:
(a) The volume of water can be calculated like:
Volume = depth x surface
In order to have coherence between units we will use proportions to transform km² to m².
[tex]2.887km^{2} .\frac{(10^{3}m)^{2} }{(1km)^{2} } =2.887 \times 10^{6} m^{2}[/tex]
Then,
Volume = 22.50 m x 2.887 x 10⁶ m² = 6.496 x 10⁷ m³
(b) We can find out the total mass of mercury using proportions. We will need these relations:
1 L = 10⁻³ m³
1 pg = 10⁻¹² g
1 kg = 10³ g
[tex]6.496\times10^{7} m^{3} (H_{2}O).\frac{1L(H_{2}O)}{10^{-3}m^{3}(H_{2}O) } .\frac{18.3pg(Hg)}{1L(H_{2}O)} .\frac{10^{-12}g(Hg) }{1pg(Hg)} .\frac{1kg(Hg)}{10^{3}g(Hg) } =1.19\times 10^{-3} kg(Hg)[/tex]
