Answer:
[tex]\frac{\textup{2}}{h}[/tex]
Explanation:
Given:
Depth = h
Width = w
Length = 1
Now,
Let ρ be the density of water
Thus,
Pressure force at the bottom will be
= Pressure × Area
= ρgh × (w × 1)
also,
Pressure force at the sides will be = [tex]\frac{\textup{1}}{\textup{2}}\times[/tex] ρgh × (h × w)
Therefore,
The ratio of the pressure force at the bottom to the pressure force on the side of the tank will be
= [tex]\frac{\rho gh\times w\times1}{\frac{1}{2}\times\rho gh\times(h\timesw)}[/tex]
= [tex]\frac{\textup{2}}{h}[/tex]
