Answer:
1.005 cm³
Explanation:
Using Ideal gas equation for same mole of gas as
[tex] \frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}[/tex]
Given ,
V₁ = 0.650 cm³
V₂ = ?
P₁ = 1.54 atm
P₂ = 1.01 atm
T₁ = 12°C
T₂ = 16 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (12 + 273.15) K = 285.15 K
T₂ = (16 + 273.15) K = 289.15 K
Using above equation as:
[tex] \frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}[/tex]
[tex] \frac {{1.54}\times {0.650}}{285.15}=\frac {{1.01}\times {V_2}}{289.15}[/tex]
Solving for V₂ , we get:
V₂ = 1.005 cm³
