Answer:
The length of the rectangle is 10 inches and the width is 4 inches
Step-by-step explanation:
Let
L -----> the length of rectangle in inches
W ----> the width of rectangle in inches
we know that
The perimeter of rectangle is
[tex]P=2(L+W)[/tex]
we have
[tex]P=28\ in[/tex]
so
[tex]28=2(L+W)[/tex]
simplify
[tex]14=(L+W)[/tex] ----> equation A
[tex]L=3W-2[/tex] ----> equation B
Solve the system of equations by substitution
Substitute equation B in equation A and solve for W
[tex]14=(3W-2+W)[/tex]
[tex]14=(4W-2)[/tex]
[tex]4W=14+2[/tex]
[tex]4W=16[/tex]
[tex]W=4\ in[/tex]
Find the value of L
[tex]L=3W-2[/tex]
[tex]L=3(4)-2=10\ in[/tex]
therefore
The length of the rectangle is 10 inches and the width is 4 inches