Answer:
C
Explanation:
The kinetic energy of an object can be calculated via the following equation:
[tex]k = \frac{1}{2} m {u}^{2} [/tex]
where:
K : kinetic energy
m: mass of the object
v: its velocity
when the speed changes, the kinetic energy changes as well. Lets suppose that it doubles, as on the problem stated. Then K is increased by a factor of four. in other words...
[tex]newk = \frac{1}{2} m {(newu)}^{2} = \frac{1}{2} m {(2u)}^{2} \\ = \frac{1}{2} m(4 {u}^{2} ) = 4( \frac{1}{2} m {u}^{2} ) = 4k[/tex]
