Explanation:
It is given that,
Mass of the rocket, [tex]m=2\times 10^6\ kg[/tex]
Thrust produced by the engine, [tex]F=3.5\times 10^7\ N[/tex]
(a) The net force acting on the rocket if it takes off vertically are :
[tex]F-mg=ma[/tex]
[tex]a=\dfrac{F-mg}{m}[/tex]
[tex]a=\dfrac{3.5\times 10^7-2\times 10^6(9.8)}{2\times 10^6}[/tex]
[tex]a=7.7\ m/s^2[/tex]
(b) Final speed of the rocket, v = 120 km/h = 33.33 m/s
Let t is the time taken by the rocket to reach velocity v.It can be calculated as :
[tex]t=\dfrac{v-u}{a}[/tex]
[tex]t=\dfrac{33.33\ m/s}{7.7\ m/s^2}[/tex]
t = 4.32 seconds
Hence, this is the required solution.