Answer:
The probability that the airline books 23 people is 0.024. We can consider that overbooking is something unlikely to occur.
Step-by-step explanation:
This is binomial experiment so we can use the probability fuction of a binomial distribution:
P(x)=[tex]\frac{n!}{x!(n-x)!}[/tex]·pˣ·(1-p)ⁿ⁻ˣ
whrere:
p: is the probability of a passenger arrive for the flight (0.85)
n: number of experiments
Hence;
P(x=23)=[tex]\frac{23!}{23!(23-23)!}[/tex]·(0.85)²³·(1-0.85)²³⁻²³
P(x=23)=(0.85)²³=0.024
