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A horizontal rifle is fired at a bull's-eye. The muzzle speed of the bullet is 660 m/s. The gun is pointed directly at the center of the bull's-eye, but the bullet strikes the target 0.027 m below the center. What is the horizontal distance between the end of the rifle and the bull's-eye?

Respuesta :

pieroraue

Answer:

The answer is 48.5 m

Explanation:

First we need to know that in the y-axis there is acceleration, in specific the acceleration caused by the gravity. I consider this value as a 10 m/s2.

Then, we define the next equation for the y-axis:

[tex]V_{f} ^{2} =  V_{i} ^{2} + 2gd[/tex]

Where:

Vi = 0 (because at the beginning there is no vertical velocity)

d = 0.027

Finally we have:

Vf = 0.7348 m/s

Also, we define another equation for the y-axis:

[tex]V_{f} =  V_{i} + g*t[/tex]

we replace the variables and we have:

t = 0.07348 s

Finally, to calculate the horizontal distance, we need the next equation:

[tex]D = v*t[/tex]

Replacing the variables we have as a result:

D = 48.5 m

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