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A person creates a game in which a person pays $5.00 to play. Then, they draw a single card from a standard
shuffled deck of cards.
If they draw a face card, they win $10.00 (i.e. they get their $5.00 back and get an extra $5.00).
If they draw an ace, they win $20.00 (i.e. they get their $5.00 back and get an extra $15.00).
With any other draw they lose their money.
What is the expected money value playing this game?
Allee sila
ITT:
SONTE
-$5.00
-$1.15
$1.31
$0.38

Respuesta :

Answer:

Step-by-step explanation:

$5.00

Answer:

Option B.

Step-by-step explanation:

Cost of game = $5.00

If they draw a face card, they win $10.00 (i.e. they get their $5.00 back and get an extra $5.00).

Winning amount = $5

Number of face cards = 12

Probability of getting a face card = [tex]\frac{12}{52}=\frac{3}{13}[/tex]

If they draw an ace, they win $20.00 (i.e. they get their $5.00 back and get an extra $15.00).

Winning amount = $15

Number of ace = 4

Probability of getting an ace  = [tex]\frac{4}{52}=\frac{1}{13}[/tex]

Any other draw they lose their money.

Number of other card (Exclude ace and face cards) = 52-4-12=36

Probability of getting other cards  = [tex]\frac{36}{52}=\frac{9}{13}[/tex]

The expected money value playing this game is

E(x) = 5 × P(face cards) + 15 × P(Ace) - 5 × P(Other cards)

[tex]E(x)=5\times \frac{3}{13}+15\times \frac{1}{13}-5\times \frac{9}{13}[/tex]

[tex]E(x)=\frac{15}{13}+\frac{15}{13}-\frac{45}{13}[/tex]

[tex]E(x)=-\frac{15}{13}[/tex]

[tex]E(x)=-1.15384615385[/tex]

[tex]E(x)\approx -1.15[/tex]

The expected money value playing this game is -$1.15

Therefore, the correct option is B.