Using the normal distribution, it is found that the z-score is of z = 0.613.
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X, and the area to the left of Z.
- The area to the right of Z is 1 subtracted by it's p-value.
In this problem, the area to the right is of 0.27, which means that z has a p-value of 1 - 0.27 = 0.73, thus z = 0.613.
A similar problem is given at https://brainly.com/question/6956996
