Answer: b.)32 years
Explanation:
According to Kepler's third law of orbital planetary motion:
The square of the period of any planet is proportional to the cube of the semi major axis of its orbit.
[tex]T^2=a^3[/tex]
where T= time period = ?
a = semi major axis = 10 AU
[tex]T^2=(10)^3[/tex]
[tex]T=\sqrt{1000}[/tex]
[tex]T=32years[/tex]
Thus the approximate orbital period of Saturn is 32 years.
