Answer:[tex]a_t=0.502 m/s^2[/tex]
Explanation:
Given
Mass of car [tex]\left ( m_c\right )=837 kg[/tex]
mass of small truck[tex]\left ( m_t\right )=1606 kg[/tex]
mass of woman[tex]\left ( m_w\right )=61 kg[/tex]
According to law of conservation of momentum
[tex]\left ( m_t+m_w\right )v_t+m_cv_c=0[/tex]
[tex]1667\times v_t=-837\times v_c[/tex]
where [tex]v_t and v_c[/tex] is the velocity of truck and car
and [tex]v_t=u+a_t\times t[/tex]
[tex]v_c=u+a_c\times t[/tex]
[tex]a_c, a_t[/tex] are the acceleration of car and truck
[tex]v_t=a_t\times t[/tex]
[tex]v_c=a_c\times t[/tex]
[tex]v_c=t[/tex]
substitute the values of [tex]v_t & v_c[/tex]
[tex]1667\times a_t\times t=-837\times t[/tex]
[tex]a_t=-0.502 m/s^2[/tex]
