10 QUESTIONS FOR THE TOTAL OF 50 POINTS!! PLEASE ANSWER QUICKLY!!!!! I NEED HELP AND FAST!!! AND WILL MARK BRAINLIEST!!!


simplify each expression! will give 10 points!

1.) 4² + (4 × 2³)

a 528 b 48 c 32 d 160

2.) (-3)⁴

a 12 b -12 c -81 d 81


evaluate the given expression for the given value will give 10 points

3.) -2n² + 5n + 9 for n=2

a 11 b -9 c -27 d 7

4.) 3x³ for x=-3

a 728 b -81 c 81 d -729

5.) 4r² - 2s³ for r=1 and s=5


will give 10 points!!! the formula for the area of a triangle is A=1/2bh , where b is the base of the triangle and h is the height of the triangle. what is the base of the triangle with an area of 30 ft² and height of 12ft?

a 3ft

b 2.5ft

c 5ft

d 10ft


will give 5 points!!!

find the area of the figure

square: s=4 2/5

a 19 9/25 in²

b 1 19/25 in²

c 3 13/25 in²

d 11/25 in²


will give 5 points!!!

use the formula d = rt to find the following: r for d= 15.4 mi and t=1.4 h

a 16.8 mi/h

b 0.09 mi/h

c 21.56 mi/h

d 11 mi/h


will give 5 points!!

Evaluate to gret the given value

( -h-3j)²/h for h=3 and j= -5

a 48

b 8

c 108

d -28


will give 10 points!!!

solve the formula for the indicated variable

m = c - ab for a

A a = m/cb

B a = c/b - m

C a = m-c/b

D a = c-m/b

Respuesta :

Answer:

  1. B) 48
  2. D) 81
  3. A) 11
  4. B) -81
  5. -246
  6. C) 5
  7. A) 19 9/25
  8. D) 11
  9. A) 48
  10. D) m-c/-b =a

Step-by-step explanation:

comment if you want the explanation, but you said you wanted it fast and it would take me like 10 minutes to right it all out

Answer:

1)b.48 2)d.81 3)a.11 4)b.–81 5)–246 c.5ft a.19 9/25 in² d.11 mi/h a.48 C.a=m–c/–b

Step-by-step explanation:

4²+(4×2³)=16+(4×8)=16+32=48

(–3)⁴=3²×3²=9×9=81

–2n²+5n+9 (n=2)

–2(2²)+5(2)+9=–2×4+5×2+9=–8+10+9=11

3x³ (x=–3)

3(–3)³=3×–27=–81

4r²–2s³ (r=1 s=5)

4×1–2×125=4–250=–246

A=½bh. ½b=A/h. b=2A/h

then b=(2×30)÷12=5ft

area of a square=s×s=

[tex]4 \times \frac{2}{5} \times 4 \times \frac{2}{5} = \frac{22}{5} \times \frac{22}{5} = \frac{484}{25} = 19 \times \frac{9}{25} {in}^{2} [/tex]

d=rt then r=d/t

then r=15.4÷1.4=11 mi/h

(–h–3j)²/h (h=3, j=–5)

(–3–3×–5)²÷3=(12)²÷3=144÷3=48

m=c–ab m–c=–ab m–c/–b=a