Answer:
The no of litres found in 3.01 moles of fluorine=68.32241L
Given:
Moles of fluorine=3mol
To Find:
No of litres present in 3mol of Fluorine.
Step by Step by Explanation:
Formula used for calculating the volume of fluorine is achieved through ideal gas equation
According to Ideal Gas;
[tex]P V=n R T[/tex]
From this above equation, volume can be calculated as
[tex]V=\frac{n R T}{P}[/tex]
Where V=Volume of the fluorine in litres
N=number of moles=3.01moles
R=Gas constant[tex]=8.3144598 L k p_{a} k^{-1} m o l^{-1}[/tex]
Under standard conditions
T=Temperature of the gas=273K
P=Pressure of the gas[tex]=100 k p_{a}[/tex]
Substitute all the values in the above equation we get
[tex]V=\frac{3.01 \times 8.3144598 \times 273}{100}[/tex]
[tex]V=\frac{6832.241}{100}[/tex]
[tex]V=68.32241 L[/tex]
Result:
Thus the no of litres found in 3.01 moles of fluorine gas is 68.32241L
