Respuesta :
Answer:
a) Mass of solid W crystallized out 0°C is 141.564 g
b) 91.92% is the percent recovery.
Explanation:
The solubility of solid W in water at 100°C = 21.3 g/100 mL
Volume of water at 100C required to dissolve 154.0 g of W: x
[tex]\frac{154.0 g}{x}=\frac{21.3 g}{100 mL}[/tex]
[tex]x=\frac{154.0 g\times 100 mL}{21.3 g}=723.0 mL[/tex]
723.0 mL of water will dissolve 154.0 grams of solid W.
The solubility of solid W in water at 0°C = 1.72 g/100 mL
Mass of W soluble in 723.00 mL of water at 0°C = m
[tex]\frac{m}{723.0 mL}=\frac{1.72 g}{100 mL}[/tex]
[tex]m=\frac{1.72 g\times 723.0 mL}{100 mL}=12.436 g[/tex]
a) Mass of solid W crystallized out 0°C : 154.0 g- 12.436 g=141.564 g
b) Percent recovery of solid at 0°C:
[tex]\frac{141.564 g}{154.0 g}\times 100=91.92\%[/tex]
91.92% is the percent recovery.
The study of chemicals and bonds is called chemistry. There are two types of elements are there and these are metals and nonmetals.
The correct answer is 77.14atm
What are moles?
- The mole is the base unit of the amount of substance in the International System of Units.
- It is defined as exactly 6.02214076×10²³ elementary entities, which may be atoms, molecules, ions, or electrons.
According to the question, the given value is as follows:-
- The solubility of solid W in water at 100°C = 21.3 g/100 mL
- The volume of water at 100C required to dissolve 154.0 g
[tex]\frac{154}{x}= \frac{21.3}{100} \\\\x=\frac{154*100}{21.3} =723.0[/tex]
Hence, 723.0 mL of water will dissolve 154.0 grams of solid W.
- The solubility of solid W in water at 0°C = 1.72 g/100 mL
- Mass of W soluble in 723.00 mL of water at 0°C = m
[tex]\frac{m}{723} =\frac{1.72}{100}\\ \\m = \frac{1.72*723}{100} = 12.436[/tex]
a) Mass of solid W crystallized out 0°C : 154.0 g- 12.436 g=141.564 g
b) Percent recovery of solid at 0°C:
[tex]\frac{141.564}{154} *100 =91.92%[/tex]
Hence, the correct answer is 91.92%.
For more information about the moles, refer to the link:-
https://brainly.com/question/16759172
