Answer:
[tex]F=1.02x10^{-3} N[/tex]
Explanation:
From the exercise we know:
[tex]m=51g*\frac{1kg}{1000g}=0.051kg[/tex]
[tex]v_{1}=-22m/s[/tex]
[tex]v_{2}=14m/s[/tex]
[tex]t_{2}-t_{1}=1800s[/tex]
So, the average acceleration is:
[tex]a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}=\frac{(14-(-22))m/s}{1800s}=0.02m/s^2[/tex]
The average force is:
[tex]F=m*a=(0.051kg)(0.02m/s^2)=1.02x10^{-3} N[/tex]
