Answer:
Step-by-step explanation:
22) J(2,-1); K(2,5)
Distance = √(x₂-x₁)² + (y₂-y₁)²
= √( 2- 2)² + (5 - [-1] )²
= √0 + (5 + 1 )²
=√ ( 6 )² = 6
25) A(0,3) ; B (0,12)
distance =√(0-0)² + (12 - 3 )²
=√( 9)² = 9
28) Q(12,-12) ; T(5,12)
distance = √(5 - 12)² + (12 - [-12] )²
= √( -7)² + (12 + 12] )²
= √ 49 + (24)²
= √ 49 + 576
= √625
=25
