Answer:
The answer to your question is:
1200 children and 800 adults
Step-by-step explanation:
Data
Children = $ 25 = c
Adults = $ 50 = a
Attendance = 2000
Revenue = $70000
# of children and adults.
c + a = 2000 (I)
25c + 50a = 70000 (II)
Multiply I by -25
-25 c - 25 a = -50000
25c + 50a = 70000
25a = 20000
a = 800
c + 800 = 2000
c = 2000 - 800
c = 1200
An equation is formed when two equal expressions. The number of child tickets sold is 1200, while the number of adult tickets sold is 800.
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Let the number of child tickets sold be x, while the number of adult tickets sold will be represented by y. Therefore, the sum of the tickets sold will be,
x + y = 2000
Solving the above equation for y we will get
y = 2000 - x
The total revenue made by selling the tickets can be written as,
25x + 50y = 70,000
Substitute the value of y,
25x + 50(2000 - x) = 70,000
25x + 100,000 - 50x = 70,000
-25x = 70,000 - 100,000
-25x = 30,000
x = 1200
Substitute the value of x in the first equation,
x + y = 2000
1200 + y = 2000
y = 800
Hence, the number of child tickets sold is 1200, while the number of adult tickets sold is 800.
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