Answer:
[tex]4c+6a\leq120\\\\4c+4a\leq100[/tex]
Step-by-step explanation:
Let c represents child bikes and a represents adult bikes.
Given : Each child bike requires 4 hours to build and 4 hours to test. Each adult bike requires 6 hours to build and 4 hours to test.
With the number of workers, the company is able to have up to 120 hours of building time and 100 hours of testing time for a week.
Then, the required system of inequality :-
[tex]4c+6a\leq120----(1)\\\\4c+4a\leq100-----(2)[/tex]
If company make 10 child bikes and 12 adult bikes in the week.
Then Put c=10 and a=12 bikes in (1) and (2).
[tex]4(10)+6(12)=40+72=112\leq120[/tex]⇒Bike order meets the restrictions
[tex]4(10)+4(12)=40+48=88\leq100[/tex]⇒Bike order meets the restrictions
Hence, the system of inequality best explains whether the company can build 10 child bikes and 12 adult bikes in the week.
[tex]4c+6a\leq120\\\\4c+4a\leq100[/tex]
Answer:
Ms.Shupp you do not help for this problem i needed help with this question then found the answer it is A
Step-by-step explanation:
