Answer:
Wet unit weight = 1.94 g/cc
Dry unit weight =1.05 g/cc
density of saturation = 0.41
porosity = 0.43
Explanation:
given data
Void ratio = 0.78
Water content -12%
Specific gravity of solids - 2.68
to find out
Wet unit weight and Dry unit weight and Degree of saturation and Porosity
solution
we know that Wet unit weight formula is
Wet unit weight = [tex]\frac{Gs + e}{1+e}[/tex] density of water
here Gs is specific gravity of soild and e is void ratio and density of water is 1
so Wet unit weight = [tex]\frac{2.68 + 0.78}{1+0.78}[/tex]
Wet unit weight = 1.94 g/cc
and
Dry unit weight = [tex]\frac{Gs - e}{1+e}[/tex] density of water
Dry unit weight = [tex]\frac{2.65 - 0.78}{1+0.78}[/tex]
Dry unit weight =1.05 g/cc
and
density of saturation is
density of saturation = Wc × [tex]\frac{Gs}{e}[/tex]
her Wc is water content
so density of saturation = 0.12 × [tex]\frac{2.68}{0.78}[/tex]
density of saturation = 0.41
and
porosity is
porosity = [tex]\frac{e}{1+e}[/tex]
porosity = [tex]\frac{0.78}{1+0.78}[/tex]
porosity = 0.43
