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The first step of the EMP and ED pathways of glucose catabolism that converts glucose into glucose 6-phosphate had a ΔGo' of 14.3kJ/mol. It is coupled with the hydrolysis of ATP to ADP, which has a ΔGo' of –31kJ/mol. What is the ΔGo' of the coupled reaction?

Respuesta :

Answer:

[tex]\Delta Go[/tex] for couple reaction is -16.7 kJ/mol

Explanation:

Given data:

[tex]\Delta Go' =14.3 kJ/mol[/tex] for glucose conversion to glucose 6 phosphate

[tex]ATP = ADP + \Delta GO' IS GIVEN AS -31 kJ/mol[/tex]

from above data we have following reaction

Glucose = Glucose 6 phosphate [tex]\Delta Go' of 14.3 kJ/mol[/tex]

[tex]ATP = ADP + \Delta Go' \ of -31 kJ/mol[/tex]

when coupling both reaction we have

Glucose + ATP = Glucose 6 phosphate + ADP

[tex]\Delta Go' of 14.3 + \Delta Go'  of -31 kJ/mol = -16.7 kJ/mol[/tex]

therefore [tex]\Delta Go[/tex] for couple reaction is -16.7 kJ/mol

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