Answer:
Since, the exponential growth function,
[tex]A=P(1+r)^{t}[/tex]
Where,
P = initial value,
t = number of periods
r = rate of increasing per period
1 + r = Growth factor per period,
(a) Here, rate of increasing per week r = 246% = 2.46,
So, the 1-week growth factor = 1 + 2.46 = 3.46
(b) Since, number of days in a week = 7,
So, the growth rate per day = [tex]\frac{2.46}{7}[/tex] ≈ 0.35
Thus, the 1-day growth factor for the mass of the bacteria = 1 +0.35 = 1.35
(c) ∵ the growth rate per day = 0.35 = 35%,
That is, the mass of bacteria increase by 35% each day ( approx )
(d) If the rate of increasing per week r = 433% = 4.33 ,
Then the rate of increasing mass per day = [tex]\frac{4.33}{7}[/tex] ≈ 0.62 = 62%
Hence, 62% would the mass increase by each day.
