Answer
(a) The probability that at most two police cruisers will drive through the neighborhood is 0.2642
(b) he probability of having 4 police is 0.2642
Step-by-step explanation:
(a) To get the probability that at most two police cruisers the neighborhood we have to consider the probability, of having 2 police, 3 police , 4 police , 5 , 6 or 7 police. All that possibilities meet my condition,
We have to add the probalities of the different possibilities to know the total probability
P=0.1839 +0.0613 +0.0153 +0.0031+ 0.0005 +0.0001=0.2642
(b) If we suppose that 2 police sighted in the neighborhoof and we are looking the probability of having 4 police , that means that 2 o more are random distribuited,
So, again , the probabily we are looking for is to have 2 o more police. Is the same calculus we made in the previus exercice.