Answer: [tex]0.4065[/tex]
Step-by-step explanation:
Given : In a sociology class there are 14 sociology majors and 11 non-sociology majors.
Total students = 14+11=25
Number of students are randomly selected = 3
Then, the number of ways to select 3 students from 25 students :-
[tex]^{25}C_3=\dfrac{25!}{(25-3)!3!}=\dfrac{25\times24\times23\times22!}{22!3!}\\\\=2300[/tex]
Number of ways to select at least 2 of the 3 students re non-sociology majors :-
[tex]^{14}C_1\times^{11}C_2+^{14}C_0\times ^{11}C_{3}\\\\=(14)\times\dfrac{11!}{2!(11-2)!}+(1)\times\dfrac{11!}{3!(11-3)!}\\\\=(14)(11\times5)+\dfrac{11\times10\times9}{6}\\\\=770+165=935[/tex]
The probability that at least 2 of the 3 students selected are non-sociology majors will be :-
[tex]\dfrac{935}{2300}=0.40652173913\approx0.4065[/tex]
