Respuesta :
Answer:
If the angle of the incline is less than the limiting angle of repose: fs < the coefficient of static friction multiplied by the normal force
Step-by-step explanation:
The friction force is variable and will depend on the external reactions.
If a body is over an inclined plane with an angle less than the limiting angle of repose, the friction force (fs) will increase as a function od the angle of inclination and will be equal to the body's weight projection parallel to the plane.
At the limiting angle of repose the friction force will be equal to the coefficient of static friction times the normal force (after that point, the body will start to slide down the plane), but at any angle less than that the friction force will always be less than the named multiplication.
Note that the coefficient of the static friction can be calculated as the tangent of the limiting angle of repose.
If the angle of the incline is less than the limiting angle of repose. Then fs < the coefficient of static friction multiplied by the normal force.
What is friction force?
It is an opposing force that opposes the motion of a body when the body tries to move. It is due to the surface roughness present between them. Irragularities get interlocked due to this friction force being generated.
A body moves when the force is just more than the friction force otherwise it will remain at rest.
When the body is placed on an inclined plane the downward force is due to the weight component along the plane. If the angle of the incline is less than the limiting angle of repose then the body remains at rest.
More about the friction link is given below.
https://brainly.com/question/13357196
