tis noteworthy that an hour has 60 minutes and thus 12 minutes is really just 12/60 of an hour, namely 1/5 hr, the rate in this case is in mph, so is using hours in it, thus we need the time to be in hours as well.
[tex]\bf\stackrel{distance}{d}=\stackrel{rate}{(110)}\stackrel{time}{\left( \cfrac{1}{5} \right)}\implies d = \cfrac{110}{5}\implies d=22~miles[/tex]
