[tex]\bf y-3=6(x+2)~\hfill \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ \stackrel{slope}{y-y_1=\stackrel{\downarrow }{m}(x-x_1)} \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{\stackrel{m}{\downarrow }}{6}[x-\stackrel{x_1}{(-2)}][/tex]
