Answer: We will reject the null hypothesis.
Step-by-step explanation:
Since we have given that
Mean μ = 71.5 lbs
Standard deviation σ = 7.5 lbs
So, the hypothesis are given below:
[tex]H_0:\mu =71.5\\\\H_1:\mu \neq 71.5[/tex]
Since α = 5% level of significance = 0.05
So, there is two tail test.
Critical values of z are 1.96 and -1.96.
So, we will reject H₀ if z<-1.96 or z>1.96
So, first we will find the value of z.
[tex]z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\\\x=\dfrac{80-71.5}{\dfrac{7.5}{\sqrt{15}}}\\\\\\z=4.39[/tex]
According to test statistic approach:
Since z >1.96
as 4.39>1.96
So, we will reject the null hypothesis.