Answer : The number of moles of [tex]NH_4Cl[/tex] and mass of [tex]NH_4Cl[/tex] is 0.50 mole and 27 grams respectively.
Solution : Given,
We are assuming that the reactant indicated in boldface is [tex]NH_3[/tex]. So,
Moles of [tex]NH_3[/tex] = 0.50 mole
Molar mass of [tex]NH_4Cl[/tex] = 53.5 g/mole
First we have to calculate the moles of [tex]NH_4Cl[/tex]
The balanced chemical reaction is,
[tex]NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)[/tex]
From the reaction, we conclude that
As, 1 mole of [tex]NH_3[/tex] react to give 1 mole of [tex]NH_4Cl[/tex]
So, 0.50 moles of [tex]NH_3[/tex] react to give 0.50 moles of [tex]NH_4Cl[/tex]
The number of moles of [tex]NH_4Cl[/tex] is, 0.50 moles.
Now we have to calculate the mass of [tex]NH_4Cl[/tex]
[tex]\text{ Mass of }NH_4Cl=\text{ Moles of }NH_4Cl\times \text{ Molar mass of }NH_4Cl[/tex]
[tex]\text{ Mass of }NH_4Cl=(0.50moles)\times (53.5g/mole)=26.75g\approx 27g[/tex]
The mass of [tex]NH_4Cl[/tex] is, 27 grams.
