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You are moving into an apartment and take the elevator to the 6th floor. Suppose your weight is 685 N and that of your belongings is 915 N. (a) Determine the work done by the elevator in lifting you and your belongings up to the 6th floor (15.2 m) at a constant velocity. (b) How much work does the elevator do on you alone (without belongings) on the downward trip, which is also made at a constant velocity

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Answer:

a) 24320 J

b) 10412 J

Explanation:

s = Displacement

F = Force or weight

Work is the amount of force being applied for a given displacement.

a) Work done

[tex]W=F\times s\\\Rightarrow W=(685+915)\times 15.2\\\Rightarrow W=24320\ J[/tex]

The work done by the elevator in lifting me and my belongings is 24320 J

b) The person's weight is 685 N

[tex]W=F\times s\\\Rightarrow W=685\times 15.2\\\Rightarrow W=10412\ J[/tex]

The work done by the elevator in lifting me is 10412 J

Answer:

(a) Work up = +24300J

(b) Work down = - 10400J

Explanation:

w up = FES = W total  S = (685N+ 915N)(15.2m)

Wup = (1600N)(15.2m) = + 24320J = 24300J

Work down = -FES= -w total S = -(685N)(15.2m)  = -10412J  = -10400J